Anda dapat memfilter alamat dengan mudah ([group] IN (48,59,60,87) OR Verified = 1)
, tetapi mengutak-atik TOP 1 akan membuat segalanya menjadi konyol (TOP (case when [group] IN (48,59,60,87) then 1 else (select count(*) from addresses where order_Id = o.order_Id) end)
. Jadi saya mengusulkan agar Anda melakukan union all
tetapi hanya untuk alamat:
SELECT TOP 1000 o.order_Id
, a.Address_Id
, a.Zip
--, *
FROM orders o
CROSS APPLY
(
select TOP 1
a.Address_Id,
a.Zip
from address a
WHERE a.order_Id = o.order_Id
AND o.[group] IN (48,59,60,87)
ORDER BY case a.Type
when 'D2' then 1
when 'K1' then 2
else 3
end,
a.ADD_DATE
UNION ALL
select
a.Address_Id,
a.Zip
from address a
WHERE a.order_Id = o.order_Id
AND o.[group] NOT IN (48,59,60,87)
AND Verified = 1
) a
WHERE
o.Status NOT IN (4, 6)
AND code1='002'
AND ((code2 IS NULL AND code3 IS NULL)
OR (code2 IN ('BIGA', 'BIGP') AND code3 IS NULL)
OR (code2 IS NULL AND code3 = 'L'))
P.S. Jika pesanan mungkin tidak memiliki alamat, ganti CROSS APPLY dengan OUTER APPLY.