Yah karena tidak mendapatkan bantuan, saya mengatasi masalah itu dan akhirnya berhasil. Ini kode kerja saya.
SIMPAN KE MySQL dari Picturebox (pbPicture)
Dim filename As String = txtName.Text + ".jpg"
Dim FileSize As UInt32
conn.Close()
Dim mstream As New System.IO.MemoryStream()
PbPicture.Image.Save(mstream, System.Drawing.Imaging.ImageFormat.Jpeg)
Dim arrImage() As Byte = mstream.GetBuffer()
FileSize = mstream.Length
Dim sqlcmd As New MySqlCommand
Dim sql As String
mstream.Close()
sql = "insert into [your table] (picture, filename, filesize)
VALUES(@File, @FileName, @FileSize)"
Try
conn.Open()
With sqlcmd
.CommandText = sql
.Connection = conn
.Parameters.AddWithValue("@FileName", filename)
.Parameters.AddWithValue("@FileSize", FileSize)
.Parameters.AddWithValue("@File", arrImage)
.ExecuteNonQuery()
End With
Catch ex As Exception
MsgBox(ex.Message)
Finally
conn.Close()
End Try
LOAD dari MySQL db Kembali ke Picturebox
Dim adapter As New MySqlDataAdapter
adapter.SelectCommand = Cmd
data = New DataTable
adapter = New MySqlDataAdapter("select picture from [yourtable]", conn)
CATATAN!! hanya dapat memasukkan satu gambar ke dalam kotak gambar, jadi tentu saja kueri ini hanya dapat mengembalikan satu rekaman untuk Anda
commandbuild = New MySqlCommandBuilder(adapter)
adapter.Fill(data)
Dim lb() As Byte = data.Rows(0).Item("picture")
Dim lstr As New System.IO.MemoryStream(lb)
PbPicture.Image = Image.FromStream(lstr)
PbPicture.SizeMode = PictureBoxSizeMode.StretchImage
lstr.Close()