Simpan banyak gambar ke mysql php dari android tetapi hanya satu gambar yang dimasukkan

Pertama-tama Anda menimpa data gambar di doInBackground Anda lingkaran.

Kedua, kode unggah PHP tidak dalam loop

JAVA

Anda seharusnya hanya memiliki satu loop, ketika Anda membangun JSON Anda, letakkan semua yang Anda butuhkan di sana

for (ImageAndText i : listItems) {
    JSONObject object = new JSONObject();

    String type = i.getType();
    String[] Type = type.split(":");
    String amount = i.getAmount();
    String[] Amount = amount.split(":");
    String description = i.getDescription();
    String[] Description = description.split(":");

    //Image
    String image = i.getImage().toString()
    Uri imageUri = Uri.parse(image);

    object.put("amount", Amount[1]);
    object.put("type", Type[1]);
    object.put("description", Description[1]);
    object.put("ts_id", id);
    object.put("image", image);
    object.put(Configs.KEY_IMAGE, getStringImage(imageUri));

    jsonArray.put(object);
}

Kemudian masukkan JSON di hashmap untuk mengirim

@Override
protected String doInBackground(String... params) {
    try {
        HashMap<String, String> data = new HashMap<String, String>();
        data.put("listItems", jsonArray.toString());

        RequestHandler rh = new RequestHandler();
        String result = rh.sendPostRequest(Configs.STAFF_BENEFIT, data);
        return result;
    } catch (Exception e) {
        return "";
    }
}

PHP

Php akan berubah, Anda tidak perlu $image = $_POST['image'];

Anda akan mendapatkan data gambar dari json $listItems = json_decode( $_POST['listItems'], true );

Anda akan meletakkan kode unggahan di loop , dan menyisipkan hanya pada unggahan yang berhasil

foreach( $listItems as $item ){ 
    $path=time()."$id.png";
    $actualpath="http://192.168.107.115:80/Android/CRUD/PhotoUpload/$path";
    $bytes=file_put_contents( $savepath, base64_decode( $item['image'] ) );
    if( !$bytes ){
        echo 'Error saving image';  
    }else{
        $stmt->bind_param('sssss', 
        $item['type'], 
        $item['amount'], 
        $item['description'], 
        $actualpath, 
        $item['ts_id'] );
        $res=$stmt->execute();
        if( !$res ) echo 'Query failed with code: '.$stmt->errno;
    }
} 

EDIT:

Skrip PHP lengkap

<?php
    if( $_SERVER['REQUEST_METHOD']=='POST' ){
        if( !empty( $_POST['listItems'] ) ){
            $listItems = json_decode( $_POST['listItems'], true ); 
            $mysqli = new mysqli("127.0.0.1:3307", "root", "", "androiddb");
            if( $mysqli->connect_errno ) echo "Failed to connect to MySQL";
            $sql="INSERT INTO `staff_benefit` 
                 ( `type`, `amount`, `description`, `image`, `ts_id` ) 
                  VALUES ( ?, ?, ?, ?, ? )";
            if($stmt=$mysqli->prepare($sql )){
                $url="http://192.168.107.115:80/Android/CRUD/PhotoUpload/";
                foreach( $listItems as $item ){ 
                    $image_name = time().".png";
                    $save_path = 'PhotoUpload/'.$image_name;
                    $image_url = $url.$image_name;
                    $bytes=file_put_contents($save_path, base64_decode($item['image']));
                    if( !$bytes ){
                        echo 'Error saving image';  
                    }else{
                        $stmt->bind_param('sssss', 
                        $item['type'], 
                        $item['amount'], 
                        $item['description'], 
                        $image_url, 
                        $item['ts_id'] );
                        if( !$res=$stmt->execute()){ 
                            echo 'Query failed with code: '.$stmt->errno;
                        }
                    }
                } 
            }
            $mysqli->close();
        }
    }
?>