MySQL - Beri peringkat pengguna di antara daftar skor tinggi teratas

Untuk versi sebelum 8.0...

SELECT *
  FROM 
     ( SELECT a.*
            , @i := @i+1 i
         FROM my_table a
         JOIN (SELECT @i:=0) vars
        ORDER 
           BY highscore DESC
            , userid 
     ) x
 WHERE name = 'jennie'
    OR i <= 3
     ORDER 
        BY i;

https://www.db-fiddle.com/f/hYsiCE1bXeTnR2HzoJkKiR/0