Mysql
 sql >> Teknologi Basis Data >  >> RDS >> Mysql

Bagaimana cara membatasi jumlah baris per nilai bidang dalam SQL?

Sayangnya mysql tidak memiliki Fungsi Analitik. Jadi, Anda harus bermain dengan variabel. Misalkan Anda memiliki bidang peningkatan otomatis:

mysql> create table mytab (
    -> id int not null auto_increment primary key,
    -> first_column int,
    -> second_column int
    -> ) engine = myisam;
Query OK, 0 rows affected (0.05 sec)

mysql> insert into mytab (first_column,second_column)
    -> values
    -> (1,1),(1,4),(2,10),(3,4),(1,4),(2,5),(1,6);
Query OK, 7 rows affected (0.00 sec)
Records: 7  Duplicates: 0  Warnings: 0

mysql> select * from mytab order by id;
+----+--------------+---------------+
| id | first_column | second_column |
+----+--------------+---------------+
|  1 |            1 |             1 |
|  2 |            1 |             4 |
|  3 |            2 |            10 |
|  4 |            3 |             4 |
|  5 |            1 |             4 |
|  6 |            2 |             5 |
|  7 |            1 |             6 |
+----+--------------+---------------+
7 rows in set (0.00 sec)

mysql> select
    -> id,
    -> first_column,
    -> second_column,
    -> row_num
    -> from (
    -> select *,
    -> @num := if(@first_column = first_column, @num:= @num + 1, 1) as row_num,
    -> @first_column:=first_column as c
    -> from mytab order by first_column,id) as t,(select @first_column:='',@num:
=0) as r;
+----+--------------+---------------+---------+
| id | first_column | second_column | row_num |
+----+--------------+---------------+---------+
|  1 |            1 |             1 |       1 |
|  2 |            1 |             4 |       2 |
|  5 |            1 |             4 |       3 |
|  7 |            1 |             6 |       4 |
|  3 |            2 |            10 |       1 |
|  6 |            2 |             5 |       2 |
|  4 |            3 |             4 |       1 |
+----+--------------+---------------+---------+
7 rows in set (0.00 sec)

mysql> select
    -> id,
    -> first_column,
    -> second_column,
    -> row_num
    -> from (
    -> select *,
    -> @num := if(@first_column = first_column, @num:= @num + 1, 1) as row_num,
    -> @first_column:=first_column as c
    -> from mytab order by first_column,id) as t,(select @first_column:='',@num:
=0) as r
    -> having row_num<=2;
+----+--------------+---------------+---------+
| id | first_column | second_column | row_num |
+----+--------------+---------------+---------+
|  1 |            1 |             1 |       1 |
|  2 |            1 |             4 |       2 |
|  3 |            2 |            10 |       1 |
|  6 |            2 |             5 |       2 |
|  4 |            3 |             4 |       1 |
+----+--------------+---------------+---------+
5 rows in set (0.02 sec)


  1. Database
  2.   
  3. Mysql
  4.   
  5. Oracle
  6.   
  7. Sqlserver
  8.   
  9. PostgreSQL
  10.   
  11. Access
  12.   
  13. SQLite
  14.   
  15. MariaDB
  1. Memanipulasi data utf8mb4 dari MySQL dengan PHP

  2. PDO - Kesalahan fatal:Panggilan ke fungsi anggota fetch() pada non-objek

  3. Memesan item dengan tag yang cocok dengan jumlah tag yang cocok

  4. Menghitung Median dengan Mysql

  5. Jenis segitiga di MySQL