Apakah Anda meminta untuk mengganti nama kolom itu sendiri atau memanfaatkan data di dalam kolom? Jika datanya sudah Anda ubah, gunakan ini:
UPDATE [yourtable]
SET word=UPPER(LEFT(word,1))+LOWER(SUBSTRING(word,2,LEN(word)))
Jika Anda hanya ingin mengubahnya hanya untuk ditampilkan dan tidak memerlukan data aktual dalam tabel untuk diubah:
SELECT UPPER(LEFT(word,1))+LOWER(SUBSTRING(word,2,LEN(word))) FROM [yourtable]
Semoga membantu.
EDIT:Saya menyadari tentang '-' jadi inilah upaya saya untuk memecahkan masalah ini dalam suatu fungsi.
CREATE FUNCTION [dbo].[CapitalizeFirstLetter]
(
--string need to format
@string VARCHAR(200)--increase the variable size depending on your needs.
)
RETURNS VARCHAR(200)
AS
BEGIN
--Declare Variables
DECLARE @Index INT,
@ResultString VARCHAR(200)--result string size should equal to the @string variable size
--Initialize the variables
SET @Index = 1
SET @ResultString = ''
--Run the Loop until END of the string
WHILE (@Index <LEN(@string)+1)
BEGIN
IF (@Index = 1)--first letter of the string
BEGIN
--make the first letter capital
SET @ResultString =
@ResultString + UPPER(SUBSTRING(@string, @Index, 1))
SET @Index = @Index+ 1--increase the index
END
-- IF the previous character is space or '-' or next character is '-'
ELSE IF ((SUBSTRING(@string, @Index-1, 1) =' 'or SUBSTRING(@string, @Index-1, 1) ='-' or SUBSTRING(@string, @Index+1, 1) ='-') and @Index+1 <> LEN(@string))
BEGIN
--make the letter capital
SET
@ResultString = @ResultString + UPPER(SUBSTRING(@string,@Index, 1))
SET
@Index = @Index +1--increase the index
END
ELSE-- all others
BEGIN
-- make the letter simple
SET
@ResultString = @ResultString + LOWER(SUBSTRING(@string,@Index, 1))
SET
@Index = @Index +1--incerase the index
END
END--END of the loop
IF (@@ERROR
<> 0)-- any error occur return the sEND string
BEGIN
SET
@ResultString = @string
END
-- IF no error found return the new string
RETURN @ResultString
END
Jadi kodenya adalah:
UPDATE [yourtable]
SET word=dbo.CapitalizeFirstLetter([STRING TO GO HERE])
