Gunakan lag()
dan jumlah kumulatif:
with query as (
select w.*,
sum(case when week < prev_week + 2 then 0 else 1 end) over (partition by animal order by week) as grp
from (select w.*,
lag(week) over (partition by animal order by week) as prev_week
from test.walk w
) w
)
select
animal, week, grp,
dense_rank() over (order by animal, grp) as grp2
from query
Catatan:Ini akan memulai kembali penghitungan untuk setiap hewan -- yang tampaknya merupakan tujuan sebenarnya dari apa yang ingin Anda lakukan. Definisi masalahnya agak rumit jika Anda ingin kelompok dipisahkan oleh hewan, tetapi menjadi inkremental. Salah satu caranya adalah:
select w.*,
sum(case when prev_week = week then 0 else 1 end) over (order by min_week, animal, week) as grp
from (select w.*,
lag(week) over (partition by animal order by week) as prev_week,
min(week) over (partition by animal) as min_week
from test.walk w
) w;