Subquery JPA masuk dari klausa

Akhirnya kami menyelesaikannya menggunakan kueri asli:

 String query = "SELECT ROUND(subquery.numberf*100/" + features + ",0) AS \"matches\", m.id_model AS \"id_model\",  m.name AS \"name\", m.brand AS \"brand\", m.url_pict AS \"url_picture\""
                + " FROM (select count(*) AS numberf, id_model AS idModel FROM model_features WHERE value LIKE '%Yes%' "
                + "AND id_feature IN(" + idFeatures + ") GROUP BY id_model) subquery, Models m WHERE subquery.numberf > 0 "
                + "AND subquery.idModel = m.id_model ORDER BY subquery.numberf DESC, m.name";
return em.createNativeQuery(query).getResultList();