Untuk membuat daftar semua anomali:
SELECT name, count(*) FROM TableA GROUP BY name HAVING count(*) > 1;
Ada beberapa cara untuk mengatasi penghapusan penipuan dan jalur Anda akan sangat bergantung pada jumlah penipuan yang Anda miliki.
Lihat ini JADI pertanyaan tentang cara menghapusnya dari tabel Anda.
Inilah solusi yang saya berikan di sana:
-- Setup for example
create table people (fname varchar(10), lname varchar(10));
insert into people values ('Bob', 'Newhart');
insert into people values ('Bob', 'Newhart');
insert into people values ('Bill', 'Cosby');
insert into people values ('Jim', 'Gaffigan');
insert into people values ('Jim', 'Gaffigan');
insert into people values ('Adam', 'Sandler');
-- Show table with duplicates
select * from people;
-- Create table with one version of each duplicate record
create table dups as
select distinct fname, lname, count(*)
from people group by fname, lname
having count(*) > 1;
-- Delete all matching duplicate records
delete people from people inner join dups
on people.fname = dups.fname AND
people.lname = dups.lname;
-- Insert single record of each dup back into table
insert into people select fname, lname from dups;
-- Show Fixed table
select * from people;