Saya menemukan jawabannya, Bagi mereka yang mencari hal yang sama di sini adalah bagaimana saya melakukannya. Anda tidak boleh mempertimbangkan untuk mengunggah gambar ke database sebagai gantinya Anda dapat menyimpan nama file yang diunggah di database Anda dan kemudian mengambil nama file dan gunakan di mana pun Anda ingin menampilkan gambar.
KODE HTML
<input type="file" name="imageUpload" id="imageUpload">
KODE PHP
if(isset($_POST['submit'])) {
//Process the image that is uploaded by the user
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["imageUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
if (move_uploaded_file($_FILES["imageUpload"]["tmp_name"], $target_file)) {
echo "The file ". basename( $_FILES["imageUpload"]["name"]). " has been uploaded.";
} else {
echo "Sorry, there was an error uploading your file.";
}
$image=basename( $_FILES["imageUpload"]["name"],".jpg"); // used to store the filename in a variable
//storind the data in your database
$query= "INSERT INTO items VALUES ('$id','$title','$description','$price','$value','$contact','$image')";
mysql_query($query);
require('heading.php');
echo "Your add has been submited, you will be redirected to your account page in 3 seconds....";
header( "Refresh:3; url=account.php", true, 303);
}
KODE UNTUK MENAMPILKAN GAMBAR
while($row = mysql_fetch_row($result)) {
echo "<tr>";
echo "<td><img src='uploads/$row[6].jpg' height='150px' width='300px'></td>";
echo "</tr>\n";
}