Hasilkan nilai DISTINCT di STRING

Inilah salah satu cara untuk melakukannya.

Karena Anda juga menginginkan jumlah yang berbeda, itu dapat dilakukan hanya dengan mengelompokkan baris dua kali. GROUP BY pertama akan menghapus duplikat, GROUP BY kedua akan menghasilkan hasil akhir.

WITH
Sitings
AS
(
    SELECT * FROM (VALUES 
    (1, 'Florida', 'Orlando', 'bird'),
    (2, 'Florida', 'Orlando', 'dog'),
    (3, 'Arizona', 'Phoenix', 'bird'),
    (4, 'Arizona', 'Phoenix', 'dog'),
    (5, 'Arizona', 'Phoenix', 'bird'),
    (6, 'Arizona', 'Phoenix', 'bird'),
    (7, 'Arizona', 'Phoenix', 'bird'),
    (8, 'Arizona', 'Flagstaff', 'dog')
    ) F (ID, State, City, Siting)
)
,CTE_Animals
AS
(
    SELECT
        State, City, Siting
    FROM Sitings
    GROUP BY State, City, Siting
)
SELECT
    State, City, COUNT(1) AS [# Of Sitings], STRING_AGG(Siting,',') AS Animals
FROM CTE_Animals
GROUP BY State, City
ORDER BY
    State
    ,City
;

Hasil

+---------+-----------+--------------+----------+
|  State  |   City    | # Of Sitings | Animals  |
+---------+-----------+--------------+----------+
| Arizona | Flagstaff |            1 | dog      |
| Arizona | Phoenix   |            2 | bird,dog |
| Florida | Orlando   |            2 | bird,dog |
+---------+-----------+--------------+----------+

Jika Anda masih mendapatkan pesan kesalahan tentang melebihi 8000 karakter, masukkan nilainya ke varchar(max) sebelum STRING_AGG .

Sesuatu seperti

STRING_AGG(CAST(Siting AS varchar(max)),',') AS Animals

Hasilkan nilai DISTINCT di STRING_AGG