Anda dapat menggunakan subquery yang memberikan peringkat ke setiap baris, sehingga di mana ada kunci duplikat (satu KB, satu lainnya) baris KB diberi peringkat lebih tinggi; lalu filter pada itu:
-- CTE for sample data
with your_table (clientkey, clientname, department, hostkey) as (
select '0201967/6', 'PPBOP1BOP01-JO,BLOGS', 'KB', 'PPBOP1BOP01/MSC/PPBOP1BOP01/2/B1KI0' from dual
union all
select '0201967/6', 'PPBOP1BOP01-JO,BLOGS', 'BS', 'PPBOP1BOP01/MSC/PPBOP1BOP01/2/B1KI0' from dual
union all
select '0024028/2', 'PPBOP1BOP01-FOO,BAR', 'KB', 'PPBOP1BOP01/MSC/PPBOP1BOP01/2/B2KI0' from dual
union all
select '0024028/2', 'PPBOP1BOP01-FOO,BAR', 'BS', 'PPBOP1BOP01/MSC/PPBOP1BOP01/2/B2KI0' from dual
union all
select '1746947/1', 'BSM1BSM03-THING,BOB', 'BS', 'BSM1BSM03/BSHVS/BSM1BSM03/2/B1KI0' from dual
union all
select '1612105/1', 'WIBU1IBU03-TREE,GREEN', 'BS', 'WIBU1IBU03/SHVS/WIBU1IBU03/3/B1KI0' from dual
)
-- actual query
select clientkey, clientname, department, hostkey
from (
select clientkey, clientname, department, hostkey,
rank () over (partition by clientkey
order by case when department = 'KB' then 0 else 1 end) as rnk
from your_table
)
where rnk = 1;
CLIENTKEY CLIENTNAME DE HOSTKEY
--------- --------------------- -- -----------------------------------
0024028/2 PPBOP1BOP01-FOO,BAR KB PPBOP1BOP01/MSC/PPBOP1BOP01/2/B2KI0
0201967/6 PPBOP1BOP01-JO,BLOGS KB PPBOP1BOP01/MSC/PPBOP1BOP01/2/B1KI0
1612105/1 WIBU1IBU03-TREE,GREEN BS WIBU1IBU03/SHVS/WIBU1IBU03/3/B1KI0
1746947/1 BSM1BSM03-THING,BOB BS BSM1BSM03/BSHVS/BSM1BSM03/2/B1KI0
Ini masih akan memungkinkan duplikat di departemen lain, jika itu bisa terjadi, dan akan mencakup semua baris itu; itu hanya akan mengecualikan duplikat untuk KB.
