LISTAGG alternatif di Oracle 10g

Coba gunakan XMLAGG seperti ini:

select
    p.PeopleID,
    rtrim(xmlagg(xmlelement(e, s.SiteName, ',')).extract('//text()').getclobval(), ',')
from people p
join site s on p.SiteID = s.SiteID
group by p.PeopleID;

Jika Anda memerlukan rangkaian dalam urutan tertentu, katakanlah urutan peningkatan SiteId, lalu tambahkan order by klausa dalam xmlagg:

select
    p.PeopleID,
    rtrim(xmlagg(xmlelement(e, s.SiteName, ',')
                   order by s.SiteId).extract('//text()').getclobval(), ',')
from people p
join site s on p.SiteID = s.SiteID
group by p.PeopleID;

EDIT:

Jika Anda ingin menampilkan hasil untuk semua orang yang ditugaskan ke situs 100:

select p.PeopleID,
    rtrim(xmlagg(
                xmlelement(e, s.SiteName, ',') order by s.SiteId
            ).extract('//text()').getclobval(), ',')
from people p
join site s on p.SiteID = s.SiteID
join (
    select distinct PeopleID
    from people
    where siteID = 1
    ) p2 on p.PeopleID = p2.PeopleID
group by p.PeopleID;