Saya memiliki program yang ingin saya bandingkan membawa tanggal dan membawa data yang diinginkan

Seharusnya sambungan luar; seperti ini:

SQL> declare
  2    descr      varchar2(90);
  3    gz_dt      date;
  4    date1      date :=to_date('2021-01-01','YYYY-MM-DD');
  5    date2      date :=to_date('2021-01-31','YYYY-MM-DD');
  6    vatt_date  date;
  7    vempcode   number;
  8    cursor c_gzdt is
  9      select g.gazzeted_date, g.description, p.att_date, p.emp_code
 10      from pay_in_out p left join gazzeted_days g
 11         on p.att_date = g.gazzeted_date
 12        and gazzeted_date between date1 and date2
 13        and p.emp_code=111
 14      order by p.att_date;
 15  begin
 16    open c_gzdt;
 17    loop
 18      fetch c_gzdt into gz_dt, descr, vatt_date, vempcode ;
 19      exit when c_gzdt%notfound;
 20
 21      if vatt_date = gz_dt then
 22         dbms_output.put_line(vatt_date||' THE DAY OF : '||descr);
 23      else
 24         dbms_output.put_line(vatt_date||' THE DAY OF : '||'PRESENT');
 25      end if;
 26
 27    end loop;
 28    close c_gzdt;
 29  end;
 30  /

yang menghasilkan

01.01.21 THE DAY OF : PRESENT
02.01.21 THE DAY OF : PRESENT
03.01.21 THE DAY OF : PRESENT
04.01.21 THE DAY OF : PRESENT
05.01.21 THE DAY OF : PRESENT
06.01.21 THE DAY OF : PRESENT
07.01.21 THE DAY OF : PRESENT
08.01.21 THE DAY OF : PRESENT
09.01.21 THE DAY OF : Its Holyday two
10.01.21 THE DAY OF : PRESENT
11.01.21 THE DAY OF : PRESENT
12.01.21 THE DAY OF : PRESENT
13.01.21 THE DAY OF : Its Holyday three
14.01.21 THE DAY OF : PRESENT
15.01.21 THE DAY OF : PRESENT
16.01.21 THE DAY OF : Its Holyday four
17.01.21 THE DAY OF : PRESENT
18.01.21 THE DAY OF : PRESENT
19.01.21 THE DAY OF : PRESENT
20.01.21 THE DAY OF : PRESENT
21.01.21 THE DAY OF : Its Holyday five
22.01.21 THE DAY OF : PRESENT
23.01.21 THE DAY OF : PRESENT
24.01.21 THE DAY OF : PRESENT
25.01.21 THE DAY OF : PRESENT
26.01.21 THE DAY OF : Its Holyday six
27.01.21 THE DAY OF : PRESENT
28.01.21 THE DAY OF : PRESENT
29.01.21 THE DAY OF : PRESENT
30.01.21 THE DAY OF : PRESENT
31.01.21 THE DAY OF : PRESENT

PL/SQL procedure successfully completed.

SQL>

Mulai Laporan Oracle masalah:lewati PL/SQL seluruhnya dan gunakan kueri kursor yang sedikit dimodifikasi sebagai kueri laporan. Pada baris #8 Anda masih akan menggunakan parameter, kemungkinan besar dibuat di bawah Parameter pengguna report laporan dalam Object Navigator. Laporan akan, saya kira, mendapatkan nilainya dari tempat lain (seperti Oracle Forms atau Apex atau ...). Hal yang sama berlaku untuk ID , saya yakin - Anda tidak benar-benar ingin melakukan hardcode 111 , kan?

SQL> select p.att_date     ||
  2       ' THE DAY OF : ' ||
  3         case when p.att_date = g.gazzeted_date then g.description
  4              else 'PRESENT'
  5         end result
  6  from pay_in_out p left join gazzeted_days g
  7     on p.att_date = g.gazzeted_date
  8    and gazzeted_date between date '2021-01-01' and date '2021-01-31'
  9    and p.emp_code = 111
 10  order by p.att_date;

RESULT
--------------------------------------------------------------
01.01.21 THE DAY OF : PRESENT
02.01.21 THE DAY OF : PRESENT
03.01.21 THE DAY OF : PRESENT
04.01.21 THE DAY OF : PRESENT
05.01.21 THE DAY OF : PRESENT
06.01.21 THE DAY OF : PRESENT
07.01.21 THE DAY OF : PRESENT
08.01.21 THE DAY OF : PRESENT
09.01.21 THE DAY OF : Its Holyday two
10.01.21 THE DAY OF : PRESENT
<snip>

[Penggabungan luar dalam Laporan]

Ah, ya ... di Laporan, Anda harus menggunakan gabungan luar Oracle "lama" (+) operator. Hal yang sama berlaku untuk case - gunakan decode sebagai gantinya:

select p.att_date     ||
     ' THE DAY OF : ' || 
       decode(p.att_date, g.gazzeted_date, g.description, 'PRESENT') result
from pay_in_out p, gazzeted_days g 
where p.att_date = g.gazzeted_date (+)
  and g.gazzeted_date (+) between date '2021-01-01' and date '2021-01-31'
  and p.emp_code = 111
order by p.att_date;