Ini akan berhasil:
SELECT a
, sum(ab_ct)::int AS ct_total
, count(*)::int AS ct_distinct_b
, array_agg(b || ', ' || ab_ct::text) AS b_arr
FROM (
SELECT a, b, count(*) AS ab_ct
FROM tbl
GROUP BY a, b
ORDER BY a, ab_ct DESC, b -- append "b" to break ties in the count
) t
GROUP BY a
ORDER BY ct_total DESC;
Pengembalian:
ct_total:jumlah totalbpera.ct_distinct_b:jumlahb. yang berbeda pera.b_arr:larikbditambah frekuensib, diurutkan berdasarkan frekuensib.
Diurutkan berdasarkan jumlah total b per a .
Atau, Anda dapat menggunakan ORDER BY klausa dalam panggilan agregat
di PostgreSQL 9.0 atau lebih baru. Seperti:
SELECT a
, sum(ab_ct)::int AS ct_total
, count(*)::int AS ct_distinct_b
, array_agg(b || ', ' || ab_ct::text ORDER BY a, ab_ct DESC, b) AS b_arr
FROM (
SELECT a, b, count(*) AS ab_ct
FROM tbl
GROUP BY a, b
) t
GROUP BY a
ORDER BY ct_total DESC; Mungkin lebih jelas. Tapi biasanya lebih lambat. Dan pengurutan baris dalam subkueri berfungsi untuk kueri sederhana seperti ini. Penjelasan lebih lanjut: